C. IS-IS
D. iBGP Answer: A
QUESTION 182 Which type of OSPF network requires manual configuration of OSPF neighbors?
A. broadcast multi-access
B. nonbroadcast multi-access
C. point-to-point
D. point-to-multipoint Answer: B
QUESTION 183 What are three reasons to control routing updates via route filtering? (Choose three)
A. To hide certain networks from the rest of the organization.
B. For easier implementation.
C. To control network overhead on the wire.
D. For simple security.
E. To prevent adjacencies from forming. Answer: C, D, E Explanation: The BGP Prefix-Based Outbound Route Filtering feature uses Border Gateway Protocol (BGP) outbound route filter (ORF) send and receive capabilities to minimize the number of BGP updates that are sent between BGP peers. Configuring this feature can help reduce the amount of system resources required for generating and processing routing updates by filtering out unwanted routing updates at the source. For example, this feature can be used to reduce the amount of processing required on a router that is not accepting full routes from a service provider network. The BGP Prefix-Based Outbound Route Filtering feature can limit the number of unwanted routing updates, which will reduce the amount of resources required for routing update generation and processing. This feature also reduces the amount of resources required to receive and discard routes that would otherwise be filtered out.
QUESTION 184 Which two features are characteristics of link-state routing protocols? (Choose two)
A. Link-state protocols are based on the Dijkstra algorithm.
B. Any incremental updates contain the full routing table.
C. Link-state protocols flood the area with LSAs when a network change occurs.
D. Routing updates are broadcast to neighbors.
E. Link-state protocols use split-horizon updates to avoid routing loops. Answer: A, C
QUESTION 185 Which three characteristics apply to IS-IS but not to OSPF? (Choose three)
A. Encapsulates PDUs directly into a data-link frame.
B. Uses a DIS and a backup DIS to present the pseudo-node on the LAN.
C. Uses stubby areas to improve network scalability.
D. Uses a default IOS metric of 10 on each interface.
E. Runs PRC (Partial Calculations) to calculate IP reachability information.
F. Uses an on-demand circuit to reduce the hello and LSA flooding across switched WAN Links, such as ISDN. Answer:
QUESTION 186 Why is Level-3 area routing an unsupported feature of integrated IS-IS on Cisco routers?
A. The System ID on a Cisco router is limited to 6 bytes.
B. The NET on a Cisco router is restricted to a maximum of 8 bytes.
C. The lack of a Domain portion of the NSAP only accommodates for 2 levels of routing hierarchy.
D. Cisco routers cannot route CLNS data that use the ISO/IEC 10589 standard of NSAP addressing.
E. Since the NSAP service identifier (N-SEL) must always be to set 00, no other service types are available. Answer:
QUESTION 187 Why should iBGP sessions be fully meshed within a Transit AS?
A. BGP requires redundant TCP sessions between iBGP peers.
B. A full mesh allows for optimal routing within the Transit AS.
C. Routes learned via iBGP are never propagated to other eBGP peers.
D. Routes learned via iBGP are never propagated to other iBGP peers.
E. Routes learned via eBGP are never propagated to other iBGP peers. Answer: E
QUESTION 188 PC1 is unable to ping PC2 successfully.
Given the above diagram and configurations, which solution would fix this problem?
A. Enable ip classless on CK1 and CK2.
B. To support discontinuous subnet, enable RIPv2 on CK1 and CK2 then enable auto-summary.
C. Enable both RIPv1 and RIPv2 on CK1 and CK2.
D. Enable no auto-summary in RIP router configuration mode on CK1 and CK2. Answer: B
QUESTION 189
Based on the P1R2 show ip bgp output, which statement is true?
A. The best path to reach the 192.168.11.0 prefix is via 10.200.200.11. B. The best path to reach the 192.168.11.0 prefix is via 10.200.200.12.
C. The best path to reach the 192.168.11.0 prefix is via both 10.200.200.11 and 10.200.200.12; BGP will automatically load balance between the two.
D. The 192.168.11.0 and 192.168.12.0 prefixes were learned via EBGP from the 10.200.200.11 and 10.200.200.12 EBGP neighbors. Answer: B
QUESTION 190 CK1# showrun interface Loopback0 ip address 10.10.10.1 255.255.255.0 ! interface Ethernet0 ip address 172.29.1.1 255.255.255.0 media-type 10BaseT ! ! router eigrp 100 redistribute connected network 172.29.0.0
no eigrp log-neighbor-changes ! ip classless no ip http server CK2# showrun interface Ethernet0 ip address 172.29.1.2 255.255.255.0 media-type 10BaseT ! interface Ethernet1 ip address 172.19.2.2 255.255.255.0 media-type 10BaseT ! router eigrp 100 network 172.19.0.0 network 172.29.0.0 ! ip classless no ip http server CK3# showrun interface Ethernet1/0 ip address 172.19.2.3 255.255.255.0
! router eigrp 100 network 172.19.0.0
no eigrp log-neighbor-changes ! ip classless ip http server With the topology found in the graphic, what will the CK1 loopback 0 be in the CK3 routing table?
A. It will show up in the routing table as D 10.0.0/8.
B. It will show up in the routing table as D EX 10.0.0.0/8.
C. It will show up in the routing table as D 10.0.0./24.
D. It will show up in CK3 routing table because there is no network command on CK1. Answer: E
