IP was created as a way to hide the complexity of physical addressing by creating a virtual addressing scheme that is independent of the underlying network. IP does not ensure that data is delivered to the
application in the appropriate order; that responsibility is left to upper-layer protocols such as TCP and UDP.
An IP address is 32 bits long. The bits can be broken down into four bytes. Each byte is expressed in decimal form and separated from other bytes by a dot (that is, x.x.x.x). This is called dotted-decimal format. Each bit within a byte carries a binary weight (starting from left to right) of 128, 64, 32, 16, 8, 4, 2, 1. If you add up these values, you get a range of 0-255 for each byte.
For example, one byte can be translated from binary format to decimal format as follows:
128 |
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64 |
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32 |
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16 |
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8 |
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4 |
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2 |
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1 |
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0 |
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1 |
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1 |
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1 |
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0 |
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0 |
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0 |
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1 |
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0 |
+ |
64 |
+ |
32 |
+ |
16 |
+ |
0 |
+ |
0 |
+ |
0 |
+ |
1 |
= |
113 |
IP addressing has been broken down into five separate classes based on the number of maximum hosts required by the network.
IP Address Classes
8 16 24 32
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Class D |
1110 |
Multicast Address |
You can see from Figure 8.2 that each address class contains a network portion and a host portion. The network portion identifies the data link that is in common with all the devices attached to that network. The host portion uniquely identifies an end device connected to the network.
Table IP Address Classes
Class Decimal Value Purpose Max, Hosts
of First Byte
Class A 0-127 Large organizations 16,777,214
Class B 128-191 Medium-sized Organizations 65,543
Class C 192-223 Small organizations 254
Class D 224-247 Multicast addresses n/a
Class E 248-255 Experimental n/a Private IP Addresses
Starting Address Ending Address
10.0.0.0 10.255.255.255
172.16.0.0 172.31.255.255
192.168.0.0 192.168.255.255
Address Masks
The network mask is used in conjunction with an IP address to delineate the network portion of an IP address from the host portion. Each major network address within its designated class has a standard network mask:
Address Class Network Mask
Class A 255.0.0.0
Class B 255.255.0.0
Class C 255.255.255.0
A major network address can be further divided into smaller networks by using a technique called subnetting. When a major network is subnetted, the address can be broken into three parts:
ü
_ The network portion
ü
_ The subnet portion
ü
_ The host portion
When a network mask is varied into further subnets like this, it is commonly referred to as a Variable Length Subnet Mask (VLSM).
Cisco often represents the subnet mask by identifying the number of bits used as the mask. For example, 192.174.10.0/30 would represent network 192.174.10.0 255.255.255.252. The value of 30 represents the number of bits used for the network portion of the address; in binary format, 30 would be
255.255.255.252 = 11111111.11111111.11111111.11111100 = 30
Let's look at another example. Given the following 170.130.0.0/21, what is the subnet mask?
21 = 11111111.11111111.11111100.00000000
The network address and mask are
170.130.0.0 255.255.248.0.
Understanding how to derive the network address and broadcast address when given an IP address and mask is critical to passing the CCIE Written Exam. Let's say that we want to determine the network address, the broadcast address, and the available addresses that
correspond with the given IP address:
150.34.74.53 255.255.240.0
1. Convert the IP address and its address mask into binary format.
150.34.74.53 = 10010110 00100010 01001010 00110101
255.255.240.0 = 11111111 11111111 11110000 00000000
2. Perform a logical AND between the IP address and the mask.
A logical AND is a digital math operation that compares two bits of data to each other. The result of the operation is as follows:
0 and 0 = 0
0 and 1 = 0
1 and 0 = 0
1 and 1 = 1
So,
Host Address: 10010110 00100010 01001010 00110101
Mask: 11111111 11111111 11110000 00000000
Logical AND Result: 10010110 00100010 01000000 00000000
3. Convert the results of the logical AND back into decimal format; this is the network address:
10010110 00100010 01000000 00000000 = 150.34.64.0
4. Calculate the broadcast address.
Remember that the network mask is used to delineate the network portion of an IP address from the host portion. Mask bits are set to 1 if the corresponding bit in the IP address should be considered part of the network address and 0 if part of the host address.
150.34.74.53 = 10010110 00100010 0100 1010 00110101
255.255.240.0 = 11111111 11111111 1111 0000 00000000
Network Bits Host Bits
To determine the broadcast address, we need to replace each bit available within the host portion of the IP address with a value of 1.
So, the broadcast address of the network for the host 150.34.74.53 is
150.34.79.255 = 10010110 00100010 0100 1111 11111111
Network Bits Host Bits
Summary:
Given the IP address and address mask: 150.34.74.53 255.255.240.0, we have determined the following:
Network Address = 150.34.64.0
Broadcast Address = 150.34.79.255
Available Addresses = 150.34.64.1-150.34.79.254 (for a total of 4,078 hosts)
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